Respuesta :

notice, is really the same.  All we do is, "insert one function into the other".

so, a way to do it is, get the value of the first one, then insert that output into the second.

[tex]\bf \begin{cases} f(x)=-x+8\\ g(x)=x^4\\ (g\circ f)(x)=g(~~f(x)~~) \end{cases} \\\\\\ (g\circ f)(2)=g(~~f(2)~~) \\\\\\ f(2)=-(2)+8\implies \boxed{f(2)=6} \\\\\\ g(~~f(2)~~)\implies g\left(~~\boxed{6}~~ \right)\implies g(6)=(6)^4\implies g(6)=1296[/tex]

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