I will use the quadratic equation to solve this: x= -b +(or minus, both) √b² + 4ac -------------------------------------------- 2a So, your numbers would be: a = 3 b = 13 c = 10 Then, solve: x = -13 +(or minus, both) √169 + 120 -------------------------------------------------- 6 = -13 +(or minus, both) 17 ------------------------------------ 6 So, first do the plus: -13 + 17 -------------- 6 = 2/3 Then do the minus: -13-17 ------------ 6 = 5
Your answer is: 2/3 and 5 ( These problems always have two answers)
