koldenka
contestada

What is the average rate of change of the function below on the interval from x = 0 to x = 2? f(x)=250(0.5)^x



-93.75


62.5


0


-0.25

Respuesta :

apologiabiology
rate of change is for (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)

y1=f(x1)
y2=f(x2)

raate of change=(f(x2)-f(x1))/(x2-x1)

find f(x2) and f(x1)

the x1=0
x2=2

f(0)=250 (remember that x^0=1)
f(2)=62.5

average rae of change is (62.5-250)/(2-0)=187.5/2=-93.75
answer is -93.75

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