lovedva
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  • 03-10-2018
  • Mathematics
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gmany
gmany gmany
  • 09-10-2018

[tex]f(x)=2x^2+5\sqrt{x-2}\\\\f(3)\to\text{put the value of x = 3 to the equation of the function}\\\\f(3)=2(3^2)+5\sqrt{3-2}=2(9)+5\sqrt1=18+5(1)=18+5=23[/tex]

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